x^2+5x+5⼀3=0的解

2025-04-13 22:38:19
推荐回答(2个)
回答1:


如上

回答2:

x^5-5x^4+ 8x^3-8x^2 +7x-3 =x^5-3x?-2x?+6x3+2x3-6x2-2x2+6x+x-3 =x?(x-3)-2x3(x-3)+2x2(x-3)-2x(x-3)+(x-3) =(x-3)(x?-2x3+2x2-2x+1) =(x-3)【(x?-2x3+x2)-(x2-2x+1)】 =(x-3)【x2(x-1)2-(x-1)2】 =(x-3)(x-1)2(x2-1) =(x-3)(x-1)2(x-1)(x+1) =(x-3)(x-1)3(x+1)