(1)
原式=(x²-y²-z²)²-(2yz)²
=(x²-y²-z²+2yz)(x²-y²-z²-2yz)
=(x²-(y-z)²)(x²-(y+z)²)
=(x+y-z)(x-y+z)(x+y+z)(x-y-z)
(2)
原式=(a-b)((a-b)²-1)
=(a-b)(a-b+1)(a-b-1)
若有帮助请点采纳
图太模糊了，看不清
这是第一题
